Two balls of mass M and 2M are thrown horizon | vedclass

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(A) The only force resisting the motion of the particle in the horizontal direction is the drag force given by $F = -kv$.According to Newton's second

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the heavier ball will hit the ground further away than the lighter ball

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(A) The only force resisting the motion of the particle in the horizontal direction is the drag force given by $F = -kv$.According to Newton's second law,$F = ma_x$,where $a_x$ is the acceleration in the $x$-direction.Therefore,$ma_x = -kv$,which implies $a_x = -\frac{kv}{m}$.This shows that the deceleration in the $x$-direction is inversely proportional to the mass of the ball.Since the lighter ball $(M)$ experiences a greater deceleration than the heavier ball $(2M)$,its horizontal velocity decreases more rapidly.Consequently,the heavier ball will travel a greater horizontal distance before hitting the ground compared to the lighter ball.

Two balls of mass $M$ and $2M$ are thrown horizontally with the same initial velocity $v_{0}$ from the top of a tall tower and experience a drag force of $-kv$ $(k > 0)$,where $v$ is the instantaneous velocity. Then,

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