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(D) The acceleration of the center of mass $(a_{CM})$ of a system is given by the formula $a_{CM} = \frac{F_{ext}}{M_{total}}$.When both balls are in

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Is equal to $g$

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(D) The acceleration of the center of mass $(a_{CM})$ of a system is given by the formula $a_{CM} = \frac{F_{ext}}{M_{total}}$.When both balls are in the air,the only external force acting on each ball is the gravitational force,which is $mg$ acting downwards.Let the masses of the two balls be $m_1$ and $m_2$. The total external force is $F_{ext} = m_1g + m_2g = (m_1 + m_2)g$.The total mass of the system is $M_{total} = m_1 + m_2$.Therefore,$a_{CM} = \frac{(m_1 + m_2)g}{m_1 + m_2} = g$.Since the acceleration due to gravity $g$ is constant and independent of the mass,velocity,or time of projection,the acceleration of the center of mass remains $g$ downwards.

Two balls are thrown in the air. The second ball is thrown $2 \ s$ after the first ball. What is the acceleration of the center of mass of the two balls while they are in the air?

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