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(C) When two balanced dice are rolled simultaneously,the total number of possible outcomes is $6 	imes 6 = 36$.Let $A$ be the event that the sum of t

Vedclass · Accepted Answer

$\frac{1}{12}$

Vedclass · Answer

(C) When two balanced dice are rolled simultaneously,the total number of possible outcomes is $6 	imes 6 = 36$.Let $A$ be the event that the sum of the numbers on the two dice is $4$.The favorable outcomes for this event are $(1, 3), (2, 2),$ and $(3, 1)$.Thus,the number of favorable outcomes is $m = 3$.The probability of the event $A$ is given by the formula $P(A) = \frac{	ext{Number of favorable outcomes}}{	ext{Total number of outcomes}}$.$P(A) = \frac{3}{36} = \frac{1}{12}$.

Two balanced dice are rolled simultaneously. Then,the probability that the sum of numbers on the dice is $4$ is .........

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