Trioxalato aluminate (III) and tetrafluoro-bo | vedclass

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Question

(C) Trioxalato aluminate $(III)$: The central metal is $Al$ with an oxidation state of $+3$. The oxalate ion $(C_2O_4^{2-})$ is a bidentate ligand wit

Vedclass · Accepted Answer

$[Al(C_2O_4)_3]^{3-} , [BF_4]^{-}$

Vedclass · Answer

(C) Trioxalato aluminate $(III)$: The central metal is $Al$ with an oxidation state of $+3$. The oxalate ion $(C_2O_4^{2-})$ is a bidentate ligand with a charge of $-2$. The coordination entity is $[Al(C_2O_4)_3]^{x}$.Calculating the charge: $x = +3 + 3(-2) = +3 - 6 = -3$. Thus,the ion is $[Al(C_2O_4)_3]^{3-}$.Tetrafluoro borate $(III)$: The central atom is $B$ with an oxidation state of $+3$. It is bonded to $4$ fluoride ions $(F^-)$,each with a charge of $-1$. The coordination entity is $[BF_4]^{y}$.Calculating the charge: $y = +3 + 4(-1) = +3 - 4 = -1$. Thus,the ion is $[BF_4]^{-}$.

Trioxalato aluminate $(III)$ and tetrafluoro-borate $(III)$ ions are :

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