Train A crosses a stationary Train B in 50 te | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Step $1$: Calculate the speed of Train $A$. Since it crosses a pole in $20 	ext{ seconds}$,the speed is $v = \frac{	ext{Length of Train } A}{	e

Vedclass · Accepted Answer

$360$

Vedclass · Answer

(A) Step $1$: Calculate the speed of Train $A$. Since it crosses a pole in $20 	ext{ seconds}$,the speed is $v = \frac{	ext{Length of Train } A}{	ext{Time}} = \frac{240 	ext{ m}}{20 	ext{ s}} = 12 	ext{ m/s}$.Step $2$: Calculate the total distance covered when crossing Train $B$. In $50 	ext{ seconds}$,the distance covered is $D = 	ext{speed} 	imes 	ext{time} = 12 	ext{ m/s} 	imes 50 	ext{ s} = 600 	ext{ meters}$.Step $3$: The total distance covered when crossing a stationary train is the sum of the lengths of both trains $(L_A + L_B)$.Therefore,$240 + L_B = 600 	ext{ meters}$.$L_B = 600 - 240 = 360 	ext{ meters}$.

Train $A$ crosses a stationary Train $B$ in $50 \text{ seconds}$ and a pole in $20 \text{ seconds}$ with the same speed. The length of Train $A$ is $240 \text{ meters}$. What is the length of the stationary Train $B$ (in meters)?

Similar Questions

$A$ car covers the first $39 \, km$ of its journey in $45 \, minutes$ and the remaining $25 \, km$ in $35 \, minutes$. What is the average speed of the car in $km/h$?

In covering a certain distance,the speeds of $A$ and $B$ are in the ratio of $3:4$. $A$ takes $30 \text{ minutes}$ more than $B$ to reach the destination. The time taken by $A$ to reach the destination is (in $\text{hours}$):

$A$ train travelling at a speed of $55\, km/hr$ travels from place $X$ to place $Y$ in $4\, hours$. If its speed is increased by $5\, km/hr$,then the time of journey is reduced by (in $minutes$):

$A$ train crosses a pole in $10 \, s$ and a platform,which is $40 \%$ longer than the length of the train,in $24 \, s$. If the length of the platform is $140 \, m$,what is the speed of the train in $m/s$?

If a $200 \, m$ long train crosses a platform of the same length as that of the train in $20 \, s$,then the speed of the train is (in $km/hr$).

Vedclass Test Series

Exam Paper Generator

Online Exam Module