Total possible stereoisomers from the given c | vedclass

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(B) The given compound is $CH_3-CH=CH-CH(OH)-CH(OH)-CH_3$. It contains $3$ stereogenic centers: $1.$ One carbon-carbon double bond $(CH=CH)$ which exh

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$8$

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(B) The given compound is $CH_3-CH=CH-CH(OH)-CH(OH)-CH_3$. It contains $3$ stereogenic centers: $1.$ One carbon-carbon double bond $(CH=CH)$ which exhibits geometrical isomerism $(cis/trans)$. $2.$ Two chiral carbon atoms $(CH(OH))$ which exhibit optical isomerism. Since the molecule is unsymmetrical,the total number of stereoisomers is calculated using the formula $2^n$,where $n$ is the total number of stereogenic centers. Here,$n = 3$. Therefore,the total number of stereoisomers $= 2^3 = 8$.

Total possible stereoisomers from the given compound $CH_3-CH=CH-CH(OH)-CH(OH)-CH_3$ will be:

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