The total number of stereoisomers of the comp | vedclass

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(D) The structure of $2,4-$dichloroheptane is $CH_3-CHCl-CH_2-CHCl-CH_2-CH_2-CH_3$.This molecule contains two chiral centers (at $C_2$ and $C_4$).Sinc

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$4$

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(D) The structure of $2,4-$dichloroheptane is $CH_3-CHCl-CH_2-CHCl-CH_2-CH_2-CH_3$.This molecule contains two chiral centers (at $C_2$ and $C_4$).Since the molecule is unsymmetrical,the number of stereoisomers is given by the formula $2^n$,where $n$ is the number of chiral centers.Here,$n = 2$.Therefore,the total number of stereoisomers $= 2^2 = 4$.

The total number of stereoisomers of the compound $2,4-$dichloroheptane is:

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