Total number of stereo-isomers possible for t | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The given compound is a $1,2$-disubstituted cyclohexane. $1$. The cyclohexane ring has two chiral centers at positions $1$ and $2$. Since the subs

Vedclass · Accepted Answer

$16$

Vedclass · Answer

(B) The given compound is a $1,2$-disubstituted cyclohexane. $1$. The cyclohexane ring has two chiral centers at positions $1$ and $2$. Since the substituents are different,the number of stereoisomers due to the ring is $2^n = 2^2 = 4$ (cis-enantiomers,trans-enantiomers). $2$. The side chain attached at position $2$ is $-	ext{CH}=	ext{CH}-	ext{CH}=	ext{CH}-	ext{CH}_2	ext{CH}_3$. This chain contains two double bonds,both of which can exhibit geometrical isomerism ($E/Z$ or $cis/trans$). $3$. The number of geometrical isomers due to the two double bonds is $2^n = 2^2 = 4$ ($E,E$; $E,Z$; $Z,E$; $Z,Z$). $4$. Since the chiral centers in the ring and the double bonds in the side chain are independent,the total number of stereoisomers is the product of the number of stereoisomers from each part: $4 	imes 4 = 16$.

Total number of stereo-isomers possible for the following compound is:
$1,2$-disubstituted cyclohexane with a $-\text{CH}_2\text{OH}$ group at position $1$ and a $-\text{CH}=\text{CH}-\text{CH}=\text{CH}-\text{CH}_2\text{CH}_3$ group at position $2$.

Similar Questions

The hydrogen indicated by the arrow will be easily removed as:

Which of the following compounds is optically inactive?

The binaphthol $(Bnp)$ is

Which of the following orders is correct for the heat of hydrogenation of these compounds?

Which of the following conformers for ethylene glycol is most stable?

Vedclass Test Series

Exam Paper Generator

Online Exam Module

Total number of stereo-isomers possible for the following compound is: $1,2$-disubstituted cyclohexane with a $-\text{CH}_2\text{OH}$ group at position $1$ and a $-\text{CH}=\text{CH}-\text{CH}=\text{CH}-\text{CH}_2\text{CH}_3$ group at position $2$.