Total number of lone pair(s) in the XeO_2F_2 | vedclass

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Question

(A) The central atom is $Xe$ (Xenon),which has $8$ valence electrons.In $XeO_2F_2$,$Xe$ forms $2$ double bonds with $O$ atoms ($4$ electrons used) and

Vedclass · Accepted Answer

$1$

Vedclass · Answer

(A) The central atom is $Xe$ (Xenon),which has $8$ valence electrons.In $XeO_2F_2$,$Xe$ forms $2$ double bonds with $O$ atoms ($4$ electrons used) and $2$ single bonds with $F$ atoms ($2$ electrons used).Total electrons used in bonding = $4 + 2 = 6$.Number of valence electrons remaining = $8 - 6 = 2$.These $2$ electrons form $1$ lone pair on the $Xe$ atom.Thus,the total number of lone pair$(s)$ on the central atom is $1$.

Total number of lone pair$(s)$ in the $XeO_2F_2$ molecule is:

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