Total number of aromatic compounds among the | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) To determine the aromaticity of the given compounds,we check for $H$ückel's rule ($4n+2$ $\pi$ electrons),planarity,and cyclic conjugation:$1$. $1

Vedclass · Accepted Answer

$2$

Vedclass · Answer

(A) To determine the aromaticity of the given compounds,we check for $H$ückel's rule ($4n+2$ $\pi$ electrons),planarity,and cyclic conjugation:$1$. $1,4$-dihydronaphthalene: Non-aromatic (not fully conjugated).$2$. Fulvalene: Non-aromatic (not fully conjugated).$3$. Cyclopentadienyl cation: Aromatic ($2$ $\pi$ electrons,$n=0$,planar,cyclic,conjugated).$4$. Cyclooctatetraene: Non-aromatic (tub-shaped,non-planar,$8$ $\pi$ electrons).$5$. Pyridine: Aromatic ($6$ $\pi$ electrons,$n=1$,planar,cyclic,conjugated).$6$. Cycloheptatriene: Non-aromatic ($sp^3$ carbon present).Thus,there are $2$ aromatic compounds (Cyclopentadienyl cation and Pyridine).

Total number of aromatic compounds among the following compounds is:

Similar Questions

Which of the following has delocalised electrons?

The electrophile that participates in the nitration of benzene is:

Which of the following is non-aromatic?

Write down the products of ozonolysis of $1,2-$dimethylbenzene ($o-$xylene). How does the result support the Kekul\text{é} structure for benzene?

The reaction ${C_6}{H_6} + C{H_3}Cl \xrightarrow{\text{anhydrous } AlCl_3} {C_6}{H_5}C{H_3} + HCl$ is an example of which of the following?

Vedclass Test Series

Exam Paper Generator

Online Exam Module