Toluene xrightarrow[Delta ]{KMnO_4} X xrighta | vedclass

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Question

(C) $1$. Oxidation of toluene with alkaline $KMnO_4$ followed by acidification yields benzoic acid $(X)$.$2$. Benzoic acid contains a $-COOH$ group,wh

Vedclass · Accepted Answer

$3-$Bromobenzoic acid

Vedclass · Answer

(C) $1$. Oxidation of toluene with alkaline $KMnO_4$ followed by acidification yields benzoic acid $(X)$.$2$. Benzoic acid contains a $-COOH$ group,which is a strongly deactivating and meta-directing group.$3$. Electrophilic aromatic substitution (bromination) of benzoic acid with $Br_2/H_2O$ (or $Br_2/FeBr_3$) occurs at the meta-position due to the electron-withdrawing nature of the $-COOH$ group.$4$. Therefore,the product $Y$ is $3$-bromobenzoic acid.

Toluene $\xrightarrow[\Delta ]{KMnO_4} X$ $\xrightarrow{Br_2/H_2O} Y$; $Y$ is

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