Toluene on reaction with reagent A gives X. T | vedclass

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(A) $1$. Toluene reacts with $CrO_2Cl_2$ in $CS_2$ followed by hydrolysis ($Etard$ reaction) to form benzaldehyde $(X)$.$2$. Benzaldehyde $(X)$ contai

Vedclass · Accepted Answer

$CrO_2Cl_2 | CS_2, H_3O^+ ; KMnO_4 | OH^-, \Delta, H_3O^+$

Vedclass · Answer

(A) $1$. Toluene reacts with $CrO_2Cl_2$ in $CS_2$ followed by hydrolysis ($Etard$ reaction) to form benzaldehyde $(X)$.$2$. Benzaldehyde $(X)$ contains a carbonyl group,so it forms $2,4-$dinitrophenylhydrazone and acts as a reducing agent towards Tollen's reagent (ammonical silver nitrate).$3$. Toluene reacts with $KMnO_4 | OH^-, \Delta$ followed by acidic workup to form benzoic acid $(Y)$.$4$. Benzoic acid $(Y)$ is acidic enough to react with $NaHCO_3$ to evolve $CO_2$ gas.$5$. Therefore,$A$ is $CrO_2Cl_2 | CS_2, H_3O^+$ and $B$ is $KMnO_4 | OH^-, \Delta, H_3O^+$.

Toluene on reaction with reagent $A$ gives $X$. This $(X)$ forms $2,4-$dinitrophenylhydrazone and reduces ammonical silver nitrate solution. Reaction of toluene with another reagent $B$ forms $Y$,which dissolves in $NaHCO_3$ with evolution of $CO_2$. What are $A$ and $B$ respectively?

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