Toluene (excess) undergoes the following sequ | vedclass

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(D) $1$. Toluene reacts with $CrO_2Cl_2$ in $CS_2$ followed by hydrolysis $(H_3O^+)$ to form benzaldehyde $(C_6H_5CHO)$ via the Etard reaction.$2$. Be

Vedclass · Accepted Answer

Residue $(A)$: $C_6H_5CH(OH)SO_3Na$,Compound $(B)$: $C_6H_5CHO$

Vedclass · Answer

(D) $1$. Toluene reacts with $CrO_2Cl_2$ in $CS_2$ followed by hydrolysis $(H_3O^+)$ to form benzaldehyde $(C_6H_5CHO)$ via the Etard reaction.$2$. Benzaldehyde then reacts with sodium bisulphite $(NaHSO_3)$ to form a crystalline addition product,which is the residue $(A)$. The structure of $(A)$ is $C_6H_5CH(OH)SO_3Na$.$3$. When this residue $(A)$ is treated with dilute $HCl$,it undergoes hydrolysis to regenerate benzaldehyde,which is compound $(B)$.$4$. Therefore,residue $(A)$ is $C_6H_5CH(OH)SO_3Na$ and compound $(B)$ is $C_6H_5CHO$.

List-$I$	List-$II$
$A. \ C_6H_5NHNH_2$	$I. \ \text{Schiff base}$
$B. \ NH_2OH$	$II. \ \text{Hydrazone}$
$C. \ C_6H_5NH_2$	$III. \ \text{Oxime}$
	$IV. \ \text{Phenyl hydrazone}$

Similar Questions

$A$ in the given reaction is

Match the following reagents with the products obtained when they react with a ketone.
List-$I$ List-$II$
$A. \ C_6H_5NHNH_2$ $I. \ \text{Schiff base}$
$B. \ NH_2OH$ $II. \ \text{Hydrazone}$
$C. \ C_6H_5NH_2$ $III. \ \text{Oxime}$
$IV. \ \text{Phenyl hydrazone}$

Correct answer is:

Correct order of reactivity in nucleophilic addition reaction is:
$(i)$ Benzaldehyde
(ii) $p$-Methylbenzaldehyde
(iii) $p$-Nitrobenzaldehyde
(iv) Acetophenone

Which of the following reagents can react with both aldehydes and ketones?

Reagent $X$ in the given reaction is:
(Image shows cyclohexanone being converted to cyclohexanol with a deuterium atom attached to the same carbon as the hydroxyl group.)

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