(C) The electronic configuration of the element is $1s^2 2s^2 2p^6 3s^2 3p^6 3d^{10} 4s^1$.Since the last electron enters the $3d$ subshell,the elemen

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(C) The electronic configuration of the element is $1s^2 2s^2 2p^6 3s^2 3p^6 3d^{10} 4s^1$.Since the last electron enters the $3d$ subshell,the element belongs to the $d$-block of the periodic table.Therefore,the correct option is $(C)$.

Class 11 Chemistry Structure of Atom Quantum number, Electronic configuration and Shape of orbitals

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To which block does an element with the electronic configuration $1s^2 2s^2 2p^6 3s^2 3p^6 3d^{10} 4s^1$ belong in the periodic table?

A
$s$-block
B
$p$-block
C
$d$-block
D
$f$-block

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Class 11 Questions

Class 11

Chemistry Questions

Chapter

Structure of Atom

Subtopic

Quantum number, Electronic configuration and Shape of orbitals

The number of unpaired electrons in $1s^2 2s^2 2p^3$ is:

MediumAIPMT 1990

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The orbital angular momentum of an electron in an orbital is given by $\sqrt{l(l + 1)} \cdot \frac{h}{2\pi}$. For an $s$-electron,this momentum is:

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Which of the following has the maximum number of unpaired electrons? (Atomic number of $Fe = 26$)

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Which of the following sets of quantum numbers is not possible?

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An electron has a spin quantum number $+1/2$ and magnetic quantum number $-1.$ It cannot be present in :

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To which block does an element with the electronic configuration $1s^2 2s^2 2p^6 3s^2 3p^6 3d^{10} 4s^1$ belong in the periodic table?

Similar Questions

The number of unpaired electrons in $1s^2 2s^2 2p^3$ is:

The orbital angular momentum of an electron in an orbital is given by $\sqrt{l(l + 1)} \cdot \frac{h}{2\pi}$. For an $s$-electron,this momentum is:

Which of the following has the maximum number of unpaired electrons? (Atomic number of $Fe = 26$)

Which of the following sets of quantum numbers is not possible?

An electron has a spin quantum number $+1/2$ and magnetic quantum number $-1.$ It cannot be present in :

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