To synthesise 1.0 mole of 2-methylpropan-2-o | vedclass

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(C) The reaction of ethyl ethanoate $(CH_{3}COOCH_{2}CH_{3})$ with Grignard reagent $(CH_{3}MgBr)$ proceeds in two steps:$1$. First,$1$ equivalent of

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$2$

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(C) The reaction of ethyl ethanoate $(CH_{3}COOCH_{2}CH_{3})$ with Grignard reagent $(CH_{3}MgBr)$ proceeds in two steps:$1$. First,$1$ equivalent of $CH_{3}MgBr$ attacks the carbonyl carbon of the ester,leading to the elimination of the ethoxide group and the formation of acetone $(CH_{3}COCH_{3})$.$2$. Second,another equivalent of $CH_{3}MgBr$ attacks the carbonyl carbon of the formed acetone to produce a tertiary alkoxide intermediate $(CH_{3}C(OMgBr)(CH_{3})_{2})$.$3$. Upon acidic workup (hydrolysis),this intermediate yields $2-$methylpropan$-2-$ol.Thus,a total of $2$ equivalents of $CH_{3}MgBr$ are required for the complete conversion of $1$ mole of ethyl ethanoate to $1$ mole of $2-$methylpropan$-2-$ol.

To synthesise $1.0 \ mole$ of $2-$methylpropan$-2-$ol from ethyl ethanoate,how many equivalents of $CH_{3}MgBr$ reagent will be required? (Integer value)

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