To establish an instantaneous displacement current of $2\,A$ in the space between two parallel plates of a $1\,\mu F$ capacitor,the potential difference across the capacitor plates will have to be changed at the rate of:

Displacement current is given by

$A$ cylindrical region contains a uniform electric field that is along the cylinder axis and is changing with time. If $r$ is the distance from the cylinder axis,the magnitude of the magnetic field within the region is:

Consider a parallel plate capacitor which is maintained at a potential of $200 \, V$. The separation distance between the plates of the capacitor and the area of the plates are $1 \, mm$ and $20 \, cm^2$, respectively. Calculate the displacement current in $1 \, \mu s$. (in $ \, mA$)

$A$ parallel plate capacitor is charged by connecting it to a battery through a resistor. If $I$ is the current in the circuit,then in the gap between the plates:

$A$ parallel plate capacitor of area $A = 16 \ cm^2$ and separation between the plates $10 \ cm$ is charged by a $DC$ current. Consider a hypothetical plane surface of area $A_0 = 3.2 \ cm^2$ inside the capacitor and parallel to the plates. At an instant,the current through the circuit is $6 \ A$. At the same instant,the displacement current through $A_0$ is . . . . . . $mA$.