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(D) The current $I$ in a mixed grouping of $n$ rows of cells,each containing $m$ cells in series,is given by $I = \frac{mnE}{mR + nr}$,where $E$ is th

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Depends upon the relative values of external and internal resistance

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(D) The current $I$ in a mixed grouping of $n$ rows of cells,each containing $m$ cells in series,is given by $I = \frac{mnE}{mR + nr}$,where $E$ is the $EMF$ of each cell,$r$ is the internal resistance,and $R$ is the external resistance.For maximum current,the denominator $(mR + nr)$ must be minimum.By the $AM$-$GM$ inequality,$mR + nr \geq 2\sqrt{mR \cdot nr}$. The minimum value occurs when $mR = nr$,or $R = \frac{nr}{m}$.Thus,the condition for maximum current depends on the relationship between the external resistance $R$ and the total internal resistance of the combination $\frac{nr}{m}$.Therefore,the correct grouping depends on the relative values of external and internal resistance.

To draw maximum current from a combination of cells,how should the cells be grouped?

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