To convert cyclononatetraene into an aromatic | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Cyclononatetraene has $9$ carbon atoms and $4$ $\pi$ bonds. To be aromatic,it must follow $H$ückel's rule,which states that a planar,cyclic,conjug

Vedclass · Accepted Answer

Loss of $H^{+}$ from $sp^3$ hybridised carbon

Vedclass · Answer

(C) Cyclononatetraene has $9$ carbon atoms and $4$ $\pi$ bonds. To be aromatic,it must follow $H$ückel's rule,which states that a planar,cyclic,conjugated system must have $(4n + 2)$ $\pi$ electrons. For $n = 2$,the system requires $10$ $\pi$ electrons. Cyclononatetraene has $8$ $\pi$ electrons. If we remove a proton $(H^+)$ from the $sp^3$ hybridized carbon (the methylene bridge),the carbon becomes $sp^2$ hybridized and carries a negative charge (a lone pair). This lone pair contributes $2$ electrons to the $\pi$ system,resulting in a total of $8 + 2 = 10$ $\pi$ electrons. Thus,the cyclononatetraenyl anion is aromatic.

To convert cyclononatetraene into an aromatic ion,the process needed is

Similar Questions

In the reaction,
$X$ and $Y$ respectively are :-

Benzene $+ 3H_2 \xrightarrow{Ni, \text{high temp.}} \text{high pressure} \, (A).$
Which of the following can be isolated as the product of this reaction?

What are $X$ and $Y$ in the following reactions?

Coal tar is the main source of $....$.

What is the correct order of decreasing reactivity for the monobromination of the following compounds?

Vedclass Test Series

Exam Paper Generator

Online Exam Module