To construct a triangle similar to a given $\triangle ABC$ with its sides being $\frac{8}{5}$ of the corresponding sides of $\triangle ABC$,a ray $BX$ is drawn such that $\angle CBX$ is an acute angle and $X$ is on the opposite side of $A$ with respect to $BC$. The minimum number of points to be located at equal distances on ray $BX$ is

$A$ circle $\odot(P, 4)$ is given. Draw a pair of tangents such that the measure of the angle between the tangents at their point of intersection $A$ is $60^\circ$.

Draw $\odot( P , 3 \, cm )$ and a diameter $\overline{ AB }$ in it. Take points $X$ and $Y$ such that $X - A - B$ and $A - B - Y$ where $PX = PY = 7 \, cm$. From $X$ and $Y$,draw tangents to $\odot( P , 3 \, cm )$. Write the steps of construction.

Draw a line segment of length $7 \, cm$. Find a point $P$ on it which divides it in the ratio $3: 5$.

Write True or False and give reasons for your answer.
To construct a triangle similar to a given $\triangle ABC$ with its sides $\frac{7}{3}$ of the corresponding sides of $\triangle ABC$,draw a ray $BX$ making an acute angle with $BC$ and $X$ lies on the opposite side of $A$ with respect to $BC$. The points $B_{1}, B_{2}, \dots, B_{7}$ are located at equal distances on $BX$,$B_{3}$ is joined to $C$ and then a line segment $B_{6}C'$ is drawn parallel to $B_{3}C$ where $C'$ lies on $BC$ produced. Finally,line segment $A'C'$ is drawn parallel to $AC$.

Divide a line segment into three parts in the ratio $2: 3: 4$ in the same order.