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(B) The average age of $5$ members $3$ years ago was $27 	ext{ years}$.The total age of these $5$ members $3$ years ago was $5 	imes 27 = 135 	ext{

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$12$

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(B) The average age of $5$ members $3$ years ago was $27 	ext{ years}$.The total age of these $5$ members $3$ years ago was $5 	imes 27 = 135 	ext{ years}$.The total age of these $5$ members at present is $135 + (5 	imes 3) = 135 + 15 = 150 	ext{ years}$.Now,a child is added,so the total number of members becomes $5 + 1 = 6$.The present average age of these $6$ members is $27 	ext{ years}$.The total age of these $6$ members at present is $6 	imes 27 = 162 	ext{ years}$.The present age of the child is the difference between the total age of $6$ members and the total age of $5$ members: $162 - 150 = 12 	ext{ years}$.

Three years ago,the average age of a family of $5$ members was $27 \text{ years}$. After the addition of a child to the family,the present average age of the family is still $27 \text{ years}$. Find the present age of the child (in years).

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