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(A) When three unbiased coins are tossed simultaneously,the total number of possible outcomes is $2^3 = 8$.The sample space is $S = \{HHH, HHT, HTH, T

Vedclass · Accepted Answer

$\frac{7}{8}$

Vedclass · Answer

(A) When three unbiased coins are tossed simultaneously,the total number of possible outcomes is $2^3 = 8$.The sample space is $S = \{HHH, HHT, HTH, THH, HTT, THT, TTH, TTT\}$.We need to find the probability of getting at most two tails.'At most two tails' means getting $0, 1,$ or $2$ tails.The only outcome that does not satisfy this condition is $TTT$ (three tails).Thus,the favorable outcomes are ${HHH, HHT, HTH, THH, HTT, THT, TTH}$,which gives $m = 7$ outcomes.Therefore,the required probability $P = \frac{m}{n} = \frac{7}{8}$.

Three unbiased coins are tossed simultaneously. Then,the probability of receiving at the most two tails is ........

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