Three successive discounts of 10 %, 12 % and | vedclass

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Question

Three successful discount equivalent to

$\left[x+y+z-\frac{x y+y z+z x}{100}+\frac{x y z}{(100)^{2}}\right] \%$

(where $x=10 \%, y=12 \%, z=15 \

Vedclass · Accepted Answer

$32.68$

Vedclass · Answer

Three successful discount equivalent to

$\left[x+y+z-\frac{x y+y z+z x}{100}+\frac{x y z}{(100)^{2}}ight] \%$

(where $x=10 \%, y=12 \%, z=15 \%)$

$\left[10+12+15-\frac{10 	imes 12+12 	imes 15+15 	imes 10}{100}+\frac{10 	imes 12 	imes 15}{(100)^{2}}ight] \%$

$37-4.50+0.18=32.68 \%$

Three successive discounts of $10 \%, 12 \%$ and $15 \%$ will amount to a single discount of in $\%$?

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