Three resistors of $5\, \Omega, 10\, \Omega$ and $15\, \Omega$ are connected in series and the combination is connected to battery of $30\, V$. Ammeter and voltmeter are connected in the circuit. Draw a circuit diagram to connect all the devices in proper correct order. What is the current flowing and potential difference across $10\, \Omega$ resistance ?
Three resistors of $5\, \Omega, 10\, \Omega$ and $15\, \Omega$ are connected in series and the combination is connected to battery of $30\, V$. Ammeter and voltmeter are connected in the circuit. Draw a circuit diagram to connect all the devices in proper correct order. What is the current flowing and potential difference across $10\, \Omega$ resistance ?
The circuit diagram is as shown
Given $\quad R _{1}=5 \Omega, R _{2}=10 \Omega, R _{3}=15 \Omega$
$V =30 V , I =?$
Since the resistors are connected in series, therefore, we hàve
$R = R _{1}+ R _{2}+ R _{3}$
$=5+10+15=30 \Omega$
Hence, $I=V / R=30 / 30=1 A$
Hence, potential across $10\, \Omega$ resistor is $V = I \times R _{2}=1 \times 10=10 V$
Similar Questions
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$A$
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$B$
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$C$
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| $A$ | $6.84 \times 10^{-8}\, \Omega m$ |
| $B$ | $1.60 \times 10^{-8}\, \Omega m$ |
| $C$ | $1.00 \times 10^{-4}\, \Omega m$ |
| $D$ | $2.50 \times 10^{12}\, \Omega m$ |
| $E$ | $4.40 \times 10^{-5}\, \Omega m$ |
| $F$ | $2.30 \times 10^{17}\, \Omega m$ |
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