Three particles $A, B$, and $C$ are thrown from the top of a tower with the same speed $u$. Particle $A$ is thrown upwards, $B$ is thrown downwards, and $C$ is thrown horizontally. If they hit the ground with speeds $V_A, V_B$, and $V_C$ respectively, then:

  • A
    $V_A = V_B = V_C$
  • B
    $V_A = V_B > V_C$
  • C
    $V_B > V_C > V_A$
  • D
    $V_A > V_B = V_C$

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