Three identical uniform thin rods each of mass $m$ and length $L$ are arranged in the $XY$ plane as shown in the figure. $A$ fourth uniform thin rod of mass $3m$ is placed as shown in the figure in the $XY$ plane. The value of length of the fourth rod such that the centre of mass of all the four rods lies at the origin is

  • A
    $3L$
  • B
    $2L$
  • C
    $\frac{L(\sqrt{2}+1)}{3}$
  • D
    $\frac{L(2\sqrt{2}+1)}{2}$

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