Three identical bulbs are connected as shown | vedclass

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Question

(a)

$P=\left(\frac{E}{2 R}\right)^2 R$

$P=\frac{E^2}{4 R}$

When $K$ is closed

$i=\frac{2 E}{3 R}$

$P^{\prime}=\frac{E^2}{9 R^2} \cdot R

Vedclass · Accepted Answer

$\frac{9 P}{4}$

Vedclass · Answer

(a)

$P=\left(\frac{E}{2 R}\right)^2 R$

$P=\frac{E^2}{4 R}$

When $K$ is closed

$i=\frac{2 E}{3 R}$

$P^{\prime}=\frac{E^2}{9 R^2} \cdot R$

$P^{\prime}=\frac{E^2}{9 R}$

$\frac{P}{P^{\prime}}=\frac{9}{4}$

$P^{\prime}=\frac{4 P}{9}$

Three identical bulbs are connected as shown in figure. When switch $S$ is closed, the power consumed in bulb $B$ is $P$. What will be the power consumed by the same bulb when switch $S$ is opened?

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