Three capacitors of capacitance $3\,\mu F$,$10\,\mu F$,and $15\,\mu F$ are connected in series to a voltage source of $100\,V$. The charge on $15\,\mu F$ is ....... $\mu C$.

$A$ capacitor of capacitance $C_1 = 1\ \mu F$ can withstand a maximum voltage $V_1 = 6\ kV$ and another capacitor of capacitance $C_2 = 3\ \mu F$ can withstand a maximum voltage $V_2 = 4\ kV$. When the two capacitors are connected in series,the combined system can withstand a maximum voltage of......$kV$.

Two capacitances of capacity $C_1$ and $C_2$ are connected in series and a potential difference $V$ is applied across the combination. The potential difference across $C_1$ will be:

Four capacitors,each of capacity $4\,\mu F$,are connected as shown in the figure. If $V_P - V_Q = 15\,V$,the energy stored in the system is . . . . . . $ergs$.

Three capacitors,each of value $1 \ \mu\text{F}$,are connected in such a way that the resultant capacitance is $1.5 \ \mu\text{F}$. Then:

Two capacitors each of capacity $2\,\mu F$ are connected in parallel. This system is connected in series with a third capacitor of $12\,\mu F$ capacity. The equivalent capacity of the system will be......$\mu F$