This symbol represents

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Question

$(A)$ The given symbol shows a $NAND$ gate where the two inputs $A$ and $B$ are shorted together to form a single input. For a $NAND$ gate, the output

Vedclass · Accepted Answer

$NOT$ gate

Vedclass · Answer

$(A)$ The given symbol shows a $NAND$ gate where the two inputs $A$ and $B$ are shorted together to form a single input. For a $NAND$ gate, the output is $Y = \overline{A \cdot B}$. Since the inputs are shorted, $A = B = X$. Therefore, the output becomes $Y = \overline{X \cdot X} = \overline{X}$. This is the Boolean expression for a $NOT$ gate. Thus, the combination acts as a $NOT$ gate.

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