(A) At the instant indicated by the dashed line,the particle is at its negative extreme position $(x = -A)$.At the extreme position,the velocity of th

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Velocity is zero,force is to the right

(A) At the instant indicated by the dashed line,the particle is at its negative extreme position $(x = -A)$.At the extreme position,the velocity of the particle is zero $(v = 0)$.The restoring force in a spring is given by $F = -kx$. Since the particle is at $x = -A$,the force is $F = -k(-A) = +kA$.$A$ positive force indicates that the force is directed towards the positive direction (to the right).Therefore,the velocity is zero and the force is to the right.

Class 11 Physics Oscillations Acceleration and Force of Simple Harmonic Motion

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This is the position-time graph of a mass on a spring. What can you say about the velocity and force at the instant indicated by the dashed line? (Positive direction is to the right.)

A
Velocity is zero,force is to the right
B
Velocity is positive,force is to the right
C
Velocity is negative,force is to the right
D
Velocity is zero,force is to the left

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Class 11

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Oscillations

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Acceleration and Force of Simple Harmonic Motion

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This is the position-time graph of a mass on a spring. What can you say about the velocity and force at the instant indicated by the dashed line? (Positive direction is to the right.)

Similar Questions

If $x, v$ and $a$ denote the displacement,the velocity and the acceleration of a particle executing simple harmonic motion of time period $T$,then,which of the following does not change with time?

$A$ particle vibrating simple harmonically has an acceleration of $16 \ cm/s^2$ when it is at a distance of $4 \ cm$ from the mean position. Its time period is: (in $s$)

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