Thirty-two persons $X_1, X_2, \ldots, X_{32}$ are randomly seated around a circular table at equal intervals. Two persons $X_i$ and $X_j$ are said to be within earshot of each other if there are at most three persons between them on the minor arc joining $X_i$ and $X_j$. The probability that $X_1$ and $X_3$ are within earshot of each other is:

  • A
    $\frac{\binom{32}{2} 30!}{8(32!)}$
  • B
    $\frac{2^{30!}}{4(32!)}$
  • C
    $\frac{8}{31}$
  • D
    $\frac{4}{31}$

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