There is some change in length when a 33000 , | vedclass

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(C) The elongation due to a tensile force is given by the formula: $\frac{\Delta l}{l} = \frac{F}{A \cdot Y}$.Given: $F = 33000 \,N$, $A = 10^{-3} \,m

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(C) The elongation due to a tensile force is given by the formula: $\frac{\Delta l}{l} = \frac{F}{A \cdot Y}$.Given: $F = 33000 \,N$, $A = 10^{-3} \,m^2$, $Y = 3 	imes 10^{11} \,N/m^2$.Substituting the values: $\frac{\Delta l}{l} = \frac{33000}{10^{-3} 	imes 3 	imes 10^{11}} = \frac{33000}{3 	imes 10^8} = 11 	imes 10^{-5}$.The elongation due to thermal expansion is given by: $\frac{\Delta l}{l} = \alpha \Delta T$.Given: $\alpha = 1.1 	imes 10^{-5} /{ }^{\circ}C$.Equating the two elongations: $11 	imes 10^{-5} = 1.1 	imes 10^{-5} 	imes \Delta T$.Solving for $\Delta T$: $\Delta T = \frac{11 	imes 10^{-5}}{1.1 	imes 10^{-5}} = 10^{\circ}C$.

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