Easy
There is no difference between a $2p$ and $3p$ orbital regarding ?
- AShape
- BSize
- CEnergy
- DValue of $n$
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Similar Questions
$1s^2 2s^2 2p^6 3s^2$ is the electronic configuration of the metal
Easy
View SolutionUsing $s$,$p$,$d$,and $f$ notations,describe the orbital with the following quantum numbers:
$(a)$ $n=1$,$l=0$
$(b)$ $n=3$,$l=1$
$(c)$ $n=4$,$l=2$
$(d)$ $n=4$,$l=3$
$(a)$ $n=1$,$l=0$
$(b)$ $n=3$,$l=1$
$(c)$ $n=4$,$l=2$
$(d)$ $n=4$,$l=3$
Medium
View SolutionIn an atom,the order of increasing energy of electrons with quantum numbers $(i)$ $n=4, l=1$,(ii) $n=4, l=0$,(iii) $n=3, l=2$,and (iv) $n=3, l=1$ is:
For which of the following sets of four quantum numbers,an electron will have the highest energy?
$n$ $l$ $m$ $s$
$n$ $l$ $m$ $s$
An electron is in one of the $3d$ orbitals. Give the possible values of $n, l,$ and $m_l$ for this electron.
Easy
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