There is no difference between a $2p$ and a $3p$ orbital regarding

Which two orbitals are located along the axes and not between the axes?

The incorrect set of quantum numbers $(n, l, m, s)$ for an electron in $3p$ orbital is

How does the orbital energy change as the nuclear charge increases from $Ne$ to $Ca$?

For the given quantum numbers $n$ and $l$ of electrons:
$(i) n = 4, l = 1$
$(ii) n = 4, l = 0$
$(iii) n = 3, l = 2$
$(iv) n = 3, l = 1$
Arrange them in the increasing order of their energy.

The configuration $1s^2 2s^2 2p^5 3s^1$ shows