There is a horizontal film of soap solution. | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) Consider a small element of the thread of length $\Delta l$ subtending an angle $	heta$ at the center. The length is given by $\Delta l = R	heta

Vedclass · Accepted Answer

$2RT$

Vedclass · Answer

(D) Consider a small element of the thread of length $\Delta l$ subtending an angle $	heta$ at the center. The length is given by $\Delta l = R	heta$.The soap film has two surfaces,so the force due to surface tension acting radially outward on the element is $F_s = 2 	imes T 	imes \Delta l = 2TR	heta$.The tension $F$ in the thread acts at both ends of the element. Resolving the tension forces,the radial component is $2F \sin(	heta/2)$.For equilibrium,the radial component of the tension must balance the force due to surface tension:$2F \sin(	heta/2) = 2TR	heta$.For small angles,$\sin(	heta/2) \approx 	heta/2$. Substituting this into the equation:$2F(	heta/2) = 2TR	heta$$F	heta = 2TR	heta$$F = 2TR$.

There is a horizontal film of soap solution. On it,a thread is placed in the form of a loop. The film is pierced inside the loop,and the thread becomes a circular loop of radius $R$. If the surface tension of the soap solution is $T$,then what will be the tension in the thread?

Similar Questions

Benzene can react with

The structure which prevents the entry of food into the respiratory tract is

The chief water conducting elements of xylem in gymnosperms are

$A$ point object is placed at the centre of a glass sphere of radius $6 \, cm$ and refractive index $1.5$. The distance of the virtual image from the surface of the sphere is.....$cm$.

$\sec ^2(\tan ^{-1} 2) + \operatorname{cosec}^2(\cot ^{-1} 3)$ is equal to

Vedclass Test Series

Exam Paper Generator

Online Exam Module