There is a 40 % increase in an amount in 8 ye | vedclass

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(D) Let the principal amount be $P = ₹ 100$.After $8$ years,the amount becomes $140 \%$ of $P$,which is $₹ 140$.Therefore,Simple Interest $(S.I)$ $= 1

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$3075$

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(D) Let the principal amount be $P = ₹ 100$.After $8$ years,the amount becomes $140 \%$ of $P$,which is $₹ 140$.Therefore,Simple Interest $(S.I)$ $= 140 - 100 = ₹ 40$.For $1$ year,$S.I = \frac{40}{8} = ₹ 5$.Since $S.I$ on $₹ 100$ for $1$ year is $₹ 5$,the rate of interest $R = 5 \%$ per annum.Now,calculate the Compound Interest $(C.I)$ on $P = ₹ 30000$ for $n = 2$ years at $r = 5 \%$ per annum.$C.I = P \left(1 + \frac{r}{100}ight)^n - P$$C.I = 30000 \left(1 + \frac{5}{100}ight)^2 - 30000$$C.I = 30000 \left(\frac{105}{100}ight)^2 - 30000$$C.I = 30000 	imes 1.1025 - 30000$$C.I = 33075 - 30000 = ₹ 3075$.

There is a $40 \%$ increase in an amount in $8$ years at simple interest. What will be the compound interest (in rupees) on ₹ $30000$ after $2$ years at the same rate?

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