There are two squares s_{1} and s_{2}. The ra | vedclass

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(B) The area of a square is given by the formula $	ext{Area} = 	ext{side}^2$.Let the sides of squares $s_{1}$ and $s_{2}$ be $a_{1}$ and $a_{2}$ res

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$15$

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(B) The area of a square is given by the formula $	ext{Area} = 	ext{side}^2$.Let the sides of squares $s_{1}$ and $s_{2}$ be $a_{1}$ and $a_{2}$ respectively.The ratio of their areas is given as $\frac{a_{1}^2}{a_{2}^2} = \frac{4}{25}$.Taking the square root of both sides,we get the ratio of their sides: $\frac{a_{1}}{a_{2}} = \sqrt{\frac{4}{25}} = \frac{2}{5}$.Given that the side of $s_{1}$ $(a_{1})$ is $6 	ext{ cm}$,we can set up the equation: $\frac{6}{a_{2}} = \frac{2}{5}$.Solving for $a_{2}$: $a_{2} = \frac{6 	imes 5}{2} = 3 	imes 5 = 15 	ext{ cm}$.Therefore,the side of $s_{2}$ is $15 	ext{ cm}$.

There are two squares $s_{1}$ and $s_{2}$. The ratio of their areas is $4:25$. If the side of $s_{1}$ is $6 \text{ cm}$,what is the side of $s_{2}$? (in $\text{cm}$)

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