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(B) Let the two mirrors be $M_1$ and $M_2$ moving away from each other with speed $v$. Let the object $O$ be at rest.For the first image $I_1$ formed

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$2nv$

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(B) Let the two mirrors be $M_1$ and $M_2$ moving away from each other with speed $v$. Let the object $O$ be at rest.For the first image $I_1$ formed by $M_1$: The object is at rest,and the mirror moves away with speed $v$. The image moves away from the mirror with speed $v$ relative to the mirror. Thus,the velocity of the image relative to the ground is $v + v = 2v$.For the first image $I_2$ formed by $M_2$: Similarly,the image moves away from the mirror with speed $v$ relative to the mirror,and the mirror moves away with speed $v$ relative to the ground. Thus,the velocity of the image relative to the ground is $2v$ in the opposite direction.As the process continues,the $n$-th image is formed by successive reflections. The velocity of the $n$-th image increases by $2v$ for each order of reflection. Specifically,the velocity of the $n$-th image is $2nv$.

There are two plane mirrors with reflecting surfaces facing each other. The mirrors are moving with speed $v$ away from each other. $A$ point object is placed between the mirrors. The velocity of the $n$-th image will be

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