There are four bulbs of power 100 ,W, 200 ,W, | vedclass

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(A) The power $P$ consumed by a bulb is given by the formula $P = \frac{V^2}{R}$, where $V$ is the voltage and $R$ is the resistance of the filament.S

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$100 \,W$ bulb

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(A) The power $P$ consumed by a bulb is given by the formula $P = \frac{V^2}{R}$, where $V$ is the voltage and $R$ is the resistance of the filament.Since the voltage source is the same for all bulbs, $V$ is constant.Therefore, the relationship between power and resistance is $R = \frac{V^2}{P}$, which implies $R \propto \frac{1}{P}$.This means that the resistance is inversely proportional to the power rating of the bulb.To have the highest resistance, the bulb must have the lowest power rating.Comparing the given powers $(100 \,W, 200 \,W, 500 \,W, 1000 \,W)$, the $100 \,W$ bulb has the lowest power.Thus, the $100 \,W$ bulb filament has the highest resistance.

There are four bulbs of power $100 \,W, 200 \,W, 500 \,W$ and $1000 \,W$. Among these, which filament has the highest resistance? (Assuming the same voltage source)

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