There are $(n + 1)$ white and $(n + 1)$ black balls,with each set numbered $1$ to $n + 1$. The number of ways in which the balls can be arranged in a row so that no two adjacent balls are of the same colour is

  • A
    $(2n + 2)!$
  • B
    $(2n + 2)! \times 2$
  • C
    $(n + 1)! \times 2$
  • D
    $2 \{(n + 1)!\}^2$

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