The Young's modulus of the material of a wire is $6 \times 10^{12} \ N/m^2$ and there is no transverse strain in it,then its modulus of rigidity will be

$A$ wire of length $L$ and radius $r$ is loaded with a weight $Mg$. If $Y$ and $\sigma$ denote the Young's modulus and Poisson's ratio of the material of the wire respectively,then the decrease in the radius of the wire $(\Delta r)$ is given by:

If the Young's modulus for silver is $8 \times 10^{10} \ N/m^2$ and the bulk modulus is $10 \times 10^{10} \ N/m^2$,what is the Poisson's ratio?

There is no change in the volume of a wire due to a change in its length on stretching. The Poisson's ratio of the material of the wire is:

On all the six surfaces of a unit cube,an equal tensile force of $F$ is applied. The increase in length of each side will be ($Y =$ Young's modulus,$\sigma =$ Poisson's ratio).

The minimum and maximum values of Poisson's ratio for a metal lie between