The work done in lifting a box onto a platform does not depend upon how fast it is lifted up. Explain your answer giving proper reasoning.

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(N/A) The work done $(W)$ in lifting a box of mass $(m)$ through a vertical height $(h)$ against the gravitational force $(F = mg)$ is given by the formula $W = F \times h = mgh$.
In this expression,the work done depends only on the mass of the object $(m)$,the acceleration due to gravity $(g)$,and the vertical displacement $(h)$.
Since the time taken or the speed at which the box is lifted does not appear in this formula,the work done is independent of the rate at which the box is lifted.

Explore More

Similar Questions

When is the work done by a force said to be negative? Give one situation in which one of the forces acting on the object is doing positive work and the other is doing negative work.

When an arrow is shot from its bow,it has kinetic energy. From where does it get the kinetic energy?

Justify,giving proper reasoning,whether the work done in the following case is positive or negative: Work done by friction on a body sliding down an inclined plane.

State the law of conservation of energy.

$(a)$ Define work. State two factors on which the magnitude of work depends.
$(b)$ $A$ car and a truck have the same speed of $30 \, m/s$. If their masses are in the ratio $1:3$,find the ratio of their kinetic energy.

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo