The work done during the expansion of a gas from a volume of $4 \ dm^3$ to $6 \ dm^3$ against a constant external pressure of $3 \ atm$ is $(1 \ L \ atm = 101.32 \ J)$ $...... \ J$
- A$+ 304$
- B$-304$
- C$-6$
- D$-608$
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