The work done against gravity in taking a $10 \, kg$ mass to a $1 \, m$ height in $1 \, s$ will be .... $J$.

$A$ force $F = (5 \hat{i} + 4 \hat{j}) \text{ N}$ acts on a body and produces a displacement $s = (6 \hat{i} - 5 \hat{j} + 3 \hat{k}) \text{ m}$. The work done by the force is: (in $\text{ J}$)

You lift a heavy book from the floor of the room and keep it in the bookshelf having a height of $2 \, m$. In this process,you take $5 \, s$. The work done by you will depend upon:

$A$ force $\vec F = 2\hat i - 3\hat j + 7\hat k \text{ (N)}$ acts on a particle which undergoes a displacement of $\vec S = 7\hat i + 3\hat j - 2\hat k \text{ (m)}$. Calculate the work done by the force in $J$.

$A$ block of mass $m$ is kept in an elevator which starts moving downward with an acceleration $a$ as shown in the figure. The block is observed by two observers $A$ and $B$ for a time interval $t_0$. According to observer $B$,the net work done on the block is

Define work exerted by force.