The weights of two iron balls are 3.5 text{ k | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) To find the percentage weight of the first ball with respect to the second ball,we use the formula:$	ext{Percentage} = \left( \frac{	ext{Weight

Vedclass · Accepted Answer

$46 \frac{2}{3} \%$

Vedclass · Answer

(A) To find the percentage weight of the first ball with respect to the second ball,we use the formula:$	ext{Percentage} = \left( \frac{	ext{Weight of first ball}}{	ext{Weight of second ball}} ight) 	imes 100$Substituting the given values:$	ext{Percentage} = \left( \frac{3.5}{7.5} ight) 	imes 100$$= \left( \frac{35}{75} ight) 	imes 100$$= \left( \frac{7}{15} ight) 	imes 100$$= \frac{700}{15} = \frac{140}{3} = 46 \frac{2}{3} \%$

The weights of two iron balls are $3.5 \text{ kg}$ and $7.5 \text{ kg}$. What is the percentage weight of the first ball with respect to the second ball?

Similar Questions

Six-elevenths of a number is equal to $22 \%$ of a second number. The second number is equal to one-fourth of a third number. The value of the third number is $2400$. What is $45 \%$ of the first number?

If the price of petrol is increased by $20 \%$,by what percentage should the consumption be decreased by the consumer,if the expenditure on petrol remains unchanged (in $\%$)?

If the height of a triangle is decreased by $40 \%$ and its base is increased by $30 \%$,what will be the effect on the area?

What percent of $12$ is $84$?

Find a single equivalent increase,if a number is successively increased by $10 \%$,$20 \%$,and $25 \%$. (in $\%$)

Vedclass Test Series

Exam Paper Generator

Online Exam Module