The weights (in $kg$) of $11$ students are given below:
$37, 42, 40, 39, 41, 35, 37, 36, 40, 40, 42$
Find the median of the data.

$A$ football player scored the following number of goals in $10$ matches:
$1, 3, 2, 5, 8, 6, 1, 4, 7, 9$
Since the number of matches is $10$ (an even number),the median is calculated as:
Median $= \frac{5^{\text{th}} \text{ observation} + 6^{\text{th}} \text{ observation}}{2}$
$= \frac{8 + 6}{2} = 7$
Is this the correct answer? If not,why?

Below is the distribution of "more than" type of marks obtained by $50$ students in a $100$ marks examination. Prepare the grouped frequency distribution from that.

Obtained marks	No. of Students
$0$ or more than $0$	$50$
$20$ or more than $20$	$48$
$40$ or more than $40$	$40$
$60$ or more than $60$	$31$
$80$ or more than $80$	$10$

The following table gives the distribution of students of sections $A$ and $B$ of a class according to the marks obtained by them.

Marks	Section $A$ Frequency	Section $B$ Frequency
$0-15$	$3$	$3$
$15-30$	$12$	$16$
$30-45$	$28$	$25$
$45-60$	$30$	$27$
$60-75$	$35$	$40$
$75-90$	$13$	$10$

Represent the marks of the students of both the sections on the same graph by two frequency polygons. What do you observe?

Represent the following data by a bar graph:

Score	Frequency
$1$	$15$
$2$	$13$
$3$	$20$
$4$	$17$
$5$	$20$
$6$	$15$

If the mean of the observations $x, x+3, x+5, x+7, x+10$ is $9,$ find the mean of the last three observations.