The wavelengths of two sound notes in air are $\frac{40}{195} \,m$ and $\frac{40}{193} \,m$. Each note produces $9$ beats per second separately with a third note of fixed frequency. The velocity of sound in air in $m/s$ is

Two tuning forks have frequencies $380 \ Hz$ and $384 \ Hz$ respectively. When they are sounded together,they produce $4$ beats per second. After hearing the maximum sound,how long will it take to hear the minimum sound in seconds?

The frequencies of two tuning forks $A$ and $B$ are $1.5 \%$ more and $2.5 \%$ less than that of the tuning fork $C$. When $A$ and $B$ are sounded together, $12$ beats are produced in $1$ second. The frequency of tuning fork $C$ is: (in $\text{ Hz}$)

Two tuning forks when sounded together produce $4$ beats/sec. The frequency of one fork is $256 \, Hz$. The number of beats heard increases when the fork of frequency $256 \, Hz$ is loaded with wax. The frequency of the other fork is (in $, Hz$)

When a tuning fork produces sound waves in air,which one of the following remains the same in the material of the tuning fork as well as in the air?

Two tuning forks of frequencies $256$ and $258$ vibrations/sec are sounded together,then the time interval between consecutive maxima heard by the observer is ..... $sec$.