The water for a factory is stored in a hemisp | vedclass

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(C) Internal diameter of the hemispherical tank $= 14\, m$.Internal radius $(r)$ of the hemispherical tank $= 14\, m / 2 = 7\, m$.Volume of the hemisp

Vedclass · Accepted Answer

$668.66$

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(C) Internal diameter of the hemispherical tank $= 14\, m$.Internal radius $(r)$ of the hemispherical tank $= 14\, m / 2 = 7\, m$.Volume of the hemispherical tank $= \frac{2}{3} \pi r^{3} = \frac{2}{3} 	imes \frac{22}{7} 	imes (7)^{3} = \frac{2}{3} 	imes 22 	imes 49 = \frac{2156}{3} \approx 718.66\, m^{3}$.The tank already contains $50$ kilolitres of water. Since $1\, m^{3} = 1000$ litres,$50$ kilolitres $= 50,000$ litres $= 50\, m^{3}$.Volume of water to be pumped into the tank $= 	ext{Total capacity} - 	ext{Existing volume} = 718.66\, m^{3} - 50\, m^{3} = 668.66\, m^{3}$.

The water for a factory is stored in a hemispherical tank whose internal diameter is $14\, m$. The tank contains $50$ kilolitres of water. Water is pumped into the tank to fill it to its capacity. Calculate the volume of water pumped into the tank. (in $, m^{3}$)

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