The volume occupied by a single CsCl ion pair | vedclass

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(D) The volume of the cube corresponding to one $CsCl$ ion pair is given as $V = 7.014 	imes 10^{-23} \ cm^{3}$.According to the problem,the smallest

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None of the above

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(D) The volume of the cube corresponding to one $CsCl$ ion pair is given as $V = 7.014 	imes 10^{-23} \ cm^{3}$.According to the problem,the smallest $Cs^{+}-Cs^{+}$ inter-nuclear distance $(a)$ is equal to the side length of this cube.Therefore,$a^{3} = 7.014 	imes 10^{-23} \ cm^{3}$.$a = (7.014 	imes 10^{-23})^{1/3} \ cm$.$a = 4.124 	imes 10^{-8} \ cm$.Since $1 \ \mathring{A} = 10^{-8} \ cm$,we have $a = 4.124 \ \mathring{A}$.Rounding to the nearest value,the distance is approximately $4.1 \ \mathring{A}$.Thus,the correct option is $D$.

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