The volume contraction of a solid copper cube of edge length $10 \ cm$,when subjected to a hydraulic pressure of $7 \times 10^6 \ Pa$,would be . . . . . . $mm^3$. (Given bulk modulus of copper $= 1.4 \times 10^{11} \ Nm^{-2}$)

The average depth of the Indian Ocean is about $3000 \,m$. The value of fractional compression $\left(\frac{\Delta V}{V}\right)$ of water at the bottom of the ocean is (given that the bulk modulus of water is $2.2 \times 10^9 \,N/m^2$,$g = 9.8 \,m/s^2$,$\rho_{H_2O} = 1000 \,kg/m^3$):

$A$ solid cube of copper of edge $10 \, cm$ is subjected to a hydraulic pressure of $7 \times 10^6 \, Pa$. If the Bulk modulus of copper is $140 \, GPa$,then the contraction in its volume will be ................ $m^3$.

When a rubber ball is taken to a depth of $h$ meters in deep sea,its volume decreases by $0.5\, \%$. Calculate the depth $h$. (Given: Bulk modulus of rubber $B = 9.8 \times 10^{8} \, \text{N/m}^2$,Density of sea water $\rho = 10^{3} \, \text{kg/m}^3$,$g = 9.8 \, \text{m/s}^2$)

The adiabatic elasticity of a gas is equal to

The increase in pressure required to decrease the volume of a water sample by $0.2 \%$ is $\text{P} \times 10^5 \text{Nm}^{-2}$. Bulk modulus of water is $2.15 \times 10^9 \text{Nm}^{-2}$. The value of $\text{P}$ is . . . . . . .