The voltmeter has a range of $10 \ V$ and its internal resistance is $50 \ \Omega$. To increase the range of the voltmeter to $15 \ V$,the resistance which is to be connected is:

  • A
    $125 \ \Omega$ resistance in parallel
  • B
    $125 \ \Omega$ resistance in series
  • C
    $25 \ \Omega$ resistance in parallel
  • D
    $25 \ \Omega$ resistance in series

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Similar Questions

$A$ galvanometer coil has a resistance of $15\; \Omega$ and the meter shows full-scale deflection for a current of $4\; mA$. How will you convert the meter into an ammeter of range $0$ to $6\; A$?

$A$ galvanometer can be converted into an ammeter by connecting:

The resistance of an ammeter is $13\, \Omega$ and its scale is graduated for a current up to $100\, A$. After an additional shunt has been connected to this ammeter,it becomes possible to measure currents up to $750\, A$ by this meter. The value of the shunt resistance is:

To convert a $800\, mV$ range millivoltmeter of resistance $40\,\Omega$ into an ammeter of $100\, mA$ range,the resistance to be connected as a shunt is .............. $\Omega$.

$A$ galvanometer acting as a voltmeter should have . . . . . . .

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